Question
Mercury has a density of 13.6g/cm^3. What volume of mercury must be taken to obtain 225g of the metal?
Answers
GPT-4o mini
To find the volume of mercury required to obtain 225g of the metal, we can use the formula that relates mass, density, and volume:
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
We can rearrange this formula to solve for volume:
\[
\text{Volume} = \frac{\text{Mass}}{\text{Density}}
\]
Given:
- Mass of mercury = 225 g
- Density of mercury = 13.6 g/cm³
Now, we can substitute the values into the formula:
\[
\text{Volume} = \frac{225 \, \text{g}}{13.6 \, \text{g/cm}^3}
\]
Calculating it:
\[
\text{Volume} = \frac{225}{13.6} \approx 16.57 \, \text{cm}^3
\]
Therefore, the volume of mercury needed to obtain 225g of the metal is approximately **16.57 cm³**.
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
We can rearrange this formula to solve for volume:
\[
\text{Volume} = \frac{\text{Mass}}{\text{Density}}
\]
Given:
- Mass of mercury = 225 g
- Density of mercury = 13.6 g/cm³
Now, we can substitute the values into the formula:
\[
\text{Volume} = \frac{225 \, \text{g}}{13.6 \, \text{g/cm}^3}
\]
Calculating it:
\[
\text{Volume} = \frac{225}{13.6} \approx 16.57 \, \text{cm}^3
\]
Therefore, the volume of mercury needed to obtain 225g of the metal is approximately **16.57 cm³**.