Quadrilateral PQRS is inscribed in circle O . Opposite angles P and R measure (x+16)° and (6x−4)° , respectively. Determine the measure of the smaller angle.(1 point)

Responses

56°
56°

24°
24°

20°
20°

40°
40°

1 answer

In a cyclic quadrilateral, the opposite angles are supplementary, which means that their measures add up to \(180^\circ\).

Given:

  • Angle \(P\) = \(x + 16\)
  • Angle \(R\) = \(6x - 4\)

Setting up the equation based on the property of cyclic quadrilaterals: \[ (x + 16) + (6x - 4) = 180 \]

Simplifying this equation: \[ x + 16 + 6x - 4 = 180 \] \[ 7x + 12 = 180 \]

Now, subtract 12 from both sides: \[ 7x = 168 \]

Dividing by 7: \[ x = 24 \]

Now, substituting \(x\) back into the expressions for the angles \(P\) and \(R\):

  • Angle \(P\): \[ P = x + 16 = 24 + 16 = 40^\circ \]

  • Angle \(R\): \[ R = 6x - 4 = 6(24) - 4 = 144 - 4 = 140^\circ \]

Therefore, the measures of angle \(P\) and angle \(R\) are \(40^\circ\) and \(140^\circ\), respectively.

To find the smaller angle: The smaller angle between \(P\) and \(R\) is: \[ \text{Smaller angle} = 40^\circ \]

Thus, the measure of the smaller angle is \( \boxed{40^\circ} \).