Question
Anand models a can of ground coffee as a right cylinder. He measures its radius as one half
2
1
in and its volume as 4 cubic inches. Find the height of the can in inches. Round your answer to the nearest tenth if necessary.
2
1
in and its volume as 4 cubic inches. Find the height of the can in inches. Round your answer to the nearest tenth if necessary.
Answers
Answered by
GPT-4o mini
To find the height of the can of ground coffee modeled as a right cylinder, we can use the formula for the volume of a cylinder:
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height.
From the problem, we know:
- \( V = 4 \) cubic inches,
- \( r = \frac{1}{2} \) inches.
Now, let's substitute the values into the volume formula and solve for \( h \):
1. Substitute the values of \( V \) and \( r \):
\[
4 = \pi \left(\frac{1}{2}\right)^2 h
\]
2. Calculate \( \left(\frac{1}{2}\right)^2 \):
\[
\left(\frac{1}{2}\right)^2 = \frac{1}{4}
\]
3. Substitute this back into the equation:
\[
4 = \pi \left(\frac{1}{4}\right) h
\]
4. Multiply both sides by 4 to eliminate the fraction:
\[
16 = \pi h
\]
5. Solve for \( h \):
\[
h = \frac{16}{\pi}
\]
6. Now, calculate \( h \) using the approximation \( \pi \approx 3.14 \):
\[
h \approx \frac{16}{3.14} \approx 5.096
\]
7. Rounding to the nearest tenth:
\[
h \approx 5.1 \text{ inches}
\]
Therefore, the height of the can is approximately **5.1 inches**.
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height.
From the problem, we know:
- \( V = 4 \) cubic inches,
- \( r = \frac{1}{2} \) inches.
Now, let's substitute the values into the volume formula and solve for \( h \):
1. Substitute the values of \( V \) and \( r \):
\[
4 = \pi \left(\frac{1}{2}\right)^2 h
\]
2. Calculate \( \left(\frac{1}{2}\right)^2 \):
\[
\left(\frac{1}{2}\right)^2 = \frac{1}{4}
\]
3. Substitute this back into the equation:
\[
4 = \pi \left(\frac{1}{4}\right) h
\]
4. Multiply both sides by 4 to eliminate the fraction:
\[
16 = \pi h
\]
5. Solve for \( h \):
\[
h = \frac{16}{\pi}
\]
6. Now, calculate \( h \) using the approximation \( \pi \approx 3.14 \):
\[
h \approx \frac{16}{3.14} \approx 5.096
\]
7. Rounding to the nearest tenth:
\[
h \approx 5.1 \text{ inches}
\]
Therefore, the height of the can is approximately **5.1 inches**.
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