Given that quadrilateral AEIU is inscribed in circle O, we have the following:
- \( m\angle A = 27^\circ \)
- \( m\angle E = 2(m\angle A) = 2 \times 27^\circ = 54^\circ \)
In a cyclic quadrilateral (one inscribed in a circle), the opposite angles are supplementary. Therefore, the following relationships hold:
\[ m\angle A + m\angle I = 180^\circ \]
\[ m\angle E + m\angle U = 180^\circ \]
Now, we can calculate \( m\angle I \):
\[ m\angle I = 180^\circ - m\angle A = 180^\circ - 27^\circ = 153^\circ \]
Next, we can calculate \( m\angle U \):
\[ m\angle U = 180^\circ - m\angle E = 180^\circ - 54^\circ = 126^\circ \]
Thus, we have:
\[ m\angle I = 153^\circ \quad \text{and} \quad m\angle U = 126^\circ \]
The answer is:
\[ m\angle I = 153^\circ \quad \text{and} \quad m\angle U = 126^\circ \]
So the correct response is:
m∠I=153° and m∠U=126°.