Question

The resistance in a circuit is halved. What happens to the voltage?

V=IR

(1 point)
Responses

The voltage is halved.
The voltage is halved.

The voltage is increased by a factor of 4.
The voltage is increased by a factor of 4.

The voltage remains the same.
The voltage remains the same.

The voltage is doubled.

Answer 1

To analyze the effect of halving the resistance on the voltage in a circuit, let's use Ohm's Law, which states:

\[ V = I \cdot R \]

If the resistance (R) is halved (let's denote the new resistance as \( R' = \frac{R}{2} \)), the equation can be rearranged to express voltage with the new resistance:

\[ V' = I \cdot R' = I \cdot \left(\frac{R}{2}\right) \]

Now, if we assume that the current (I) is constant (which it might not always be, depending on the circuit configuration), the new voltage would be:

\[ V' = I \cdot \left(\frac{R}{2}\right) = \frac{I \cdot R}{2} = \frac{V}{2} \]

In this scenario where the current remains the same, the voltage is halved.

However, if the current changes in response to the change in resistance (as it would in many circuits), we would need more information about the specific circuit setup to determine the new voltage.

In summary, under the assumption of constant current, the answer to the question is:

**The voltage is halved.**