A board game uses a spinner with three equal sections labeled A, B, and C. A player spins the wheel 60 times and records the outcomes:



A: 28 times


B: 15 times


C: 17 times

1 answer

To analyze the outcomes from the spinner, we can calculate the experimental probabilities for each section (A, B, and C) based on the number of spins and the recorded outcomes.

  1. Total Spins: The player spun the spinner a total of 60 times.

  2. Outcomes:

    • A: 28 times
    • B: 15 times
    • C: 17 times
  3. Experimental Probabilities:

    • Probability of A: \( P(A) = \frac{\text{Number of times A was spun}}{\text{Total spins}} = \frac{28}{60} \)
    • Probability of B: \( P(B) = \frac{\text{Number of times B was spun}}{\text{Total spins}} = \frac{15}{60} \)
    • Probability of C: \( P(C) = \frac{\text{Number of times C was spun}}{\text{Total spins}} = \frac{17}{60} \)
  4. Calculating the Probabilities:

    • \( P(A) = \frac{28}{60} \approx 0.4667 \)
    • \( P(B) = \frac{15}{60} = 0.25 \)
    • \( P(C) = \frac{17}{60} \approx 0.2833 \)
  5. Summary of the Results:

    • Probability of landing on A: approximately 0.467 (or 46.7%)
    • Probability of landing on B: 0.25 (or 25%)
    • Probability of landing on C: approximately 0.283 (or 28.3%)

These probabilities reflect the outcomes of the player's spins and indicate that section A was spun more frequently compared to sections B and C.