Question
apple juice in a glass has a mass of 0.25 kilograms and a volume of 320 cm^3. Which of the following correctly uses this information to calculate the density of the apple juice
Answers
GPT-4o mini
Density is defined as mass divided by volume. The formula to calculate density (ρ) is:
\[
ρ = \frac{\text{mass}}{\text{volume}}
\]
In this case, you have:
- Mass (m) = 0.25 kg
- Volume (V) = 320 cm³
To calculate the density, you can plug in the values:
\[
ρ = \frac{0.25 \text{ kg}}{320 \text{ cm}^3}
\]
Now you can perform the calculation:
\[
ρ = \frac{0.25}{320} = 0.00078125 \text{ kg/cm}^3
\]
To express the density in a more commonly used unit (g/cm³), you can convert kilograms to grams (1 kg = 1000 g):
\[
\rho = 0.00078125 \text{ kg/cm}^3 \times 1000 \text{ g/kg} = 0.78125 \text{ g/cm}^3
\]
Therefore, the density of the apple juice is approximately **0.78 g/cm³**.
So, the correct way to use the information provided to calculate density is to apply the formula \(ρ = \frac{\text{mass}}{\text{volume}}\) using the given mass and volume.
\[
ρ = \frac{\text{mass}}{\text{volume}}
\]
In this case, you have:
- Mass (m) = 0.25 kg
- Volume (V) = 320 cm³
To calculate the density, you can plug in the values:
\[
ρ = \frac{0.25 \text{ kg}}{320 \text{ cm}^3}
\]
Now you can perform the calculation:
\[
ρ = \frac{0.25}{320} = 0.00078125 \text{ kg/cm}^3
\]
To express the density in a more commonly used unit (g/cm³), you can convert kilograms to grams (1 kg = 1000 g):
\[
\rho = 0.00078125 \text{ kg/cm}^3 \times 1000 \text{ g/kg} = 0.78125 \text{ g/cm}^3
\]
Therefore, the density of the apple juice is approximately **0.78 g/cm³**.
So, the correct way to use the information provided to calculate density is to apply the formula \(ρ = \frac{\text{mass}}{\text{volume}}\) using the given mass and volume.