A triangular park is represented on a map using a scale of 1 inch = 20 yards. The park has a base of 3 inches and a height of 2 inches on the map. What is the actual area of the park in square yards?

(4 Points)

A.30 yd²

B.60 yd²

C.600 yd²

D.1,200 yd²

1 answer

To find the actual area of the triangular park represented on the map, we first need to determine its dimensions in the actual size using the given scale of the map.

  1. Convert the dimensions from inches to yards:

    • Base: \(3 \text{ inches} \times 20 \text{ yards/inch} = 60 \text{ yards}\)
    • Height: \(2 \text{ inches} \times 20 \text{ yards/inch} = 40 \text{ yards}\)
  2. Calculate the area of the triangle using the formula: \[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \]

Substituting the actual dimensions: \[ \text{Area} = \frac{1}{2} \times 60 \text{ yards} \times 40 \text{ yards} = \frac{1}{2} \times 2400 \text{ yd}^2 = 1200 \text{ yd}^2 \]

Therefore, the actual area of the park is \( \boxed{1200 \text{ yd}^2} \).

The correct answer is D. 1,200 yd².