Factor completely.

5f2–24f–5

1 answer

To factor the expression \( 5f^2 - 24f - 5 \) completely, we can follow these steps.

  1. Identify the coefficients: We have \( a = 5 \), \( b = -24 \), and \( c = -5 \).

  2. Use the quadratic formula to find roots if simple factoring doesn't seem easy: \[ f = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} \] Plugging in the values: \[ f = \frac{{24 \pm \sqrt{{(-24)^2 - 4 \cdot 5 \cdot (-5)}}}}{2 \cdot 5} \] \[ = \frac{{24 \pm \sqrt{{576 + 100}}}}{10} \] \[ = \frac{{24 \pm \sqrt{676}}}{10} \] \[ = \frac{{24 \pm 26}}{10} \]

    This gives us: \[ f_1 = \frac{{50}}{10} = 5 \] \[ f_2 = \frac{{-2}}{10} = -0.2 \]

  3. Express the quadratic as: \[ 5f^2 - 24f - 5 = 5(f - 5)(f + 0.2) \]

  4. Rewrite the fractional root as an integer by multiplying through by 10: \[ 5(f - 5)(10f + 2) \]

  5. Final factored form: The expression can be factored completely as: \[ 5(f - 5)(10f + 2) \]

To summarize, the completely factored form of \( 5f^2 - 24f - 5 \) is: \[ 5(f - 5)(10f + 2) \]