Applying the formula V=B×h

, what is the volume of a rectangular prism with a length of 11 1/5
in., a width of 9 1/2
in., and a height of 8 1/2
in.?(1 point)
Responses

29 1/5in.3
29 Start Fraction 1 over 5 end fraction in cubed

96,228 4/25in.3
96,228 Start Fraction 4 over 25 end fraction in cubed

904 2/5in.3
904 Start Fraction 2 over 5 end fraction in cubed

106 2/5in.3
106 Start Fraction 2 over 5 end fraction in cubed

1 answer

To find the volume of a rectangular prism, the formula used is:

\[ V = B \times h \]

where \( B \) is the base area (length × width) and \( h \) is the height.

Let's calculate the volume for the given dimensions: length = \( 11 \frac{1}{5} \) inches, width = \( 9 \frac{1}{2} \) inches, and height = \( 8 \frac{1}{2} \) inches.

  1. Convert the mixed numbers into improper fractions:

    • Length: \[ 11 \frac{1}{5} = \frac{11 \times 5 + 1}{5} = \frac{55 + 1}{5} = \frac{56}{5} \]
    • Width: \[ 9 \frac{1}{2} = \frac{9 \times 2 + 1}{2} = \frac{18 + 1}{2} = \frac{19}{2} \]
    • Height: \[ 8 \frac{1}{2} = \frac{8 \times 2 + 1}{2} = \frac{16 + 1}{2} = \frac{17}{2} \]
  2. Calculate the base area \( B \): \[ B = \text{length} \times \text{width} = \left( \frac{56}{5} \right) \times \left( \frac{19}{2} \right) \] \[ B = \frac{56 \times 19}{5 \times 2} = \frac{1064}{10} = \frac{532}{5} \]

  3. Now calculate the volume \( V \): \[ V = B \times h = \left( \frac{532}{5} \right) \times \left( \frac{17}{2} \right) \] \[ V = \frac{532 \times 17}{5 \times 2} = \frac{9054}{10} = 905.4 = 905 \frac{2}{5} \]

Thus, the volume of the rectangular prism is

\[ 904 \frac{2}{5} \text{ in}^3 \]

Therefore, the correct response is:

904 2/5 in³