Question
A spinner is divided into three sections. The sector labeled is four times as large as each of the sectors labeled and , which are of equal size.
The procedure below is intended to simulate the behavior of the spinner.
Question
11
Mark for Review
Which of the following can be used to replace so that the procedure correctly simulates the spinner?
Option A,Image with alt text: The block code consists of 6 lines. Line 1: spin, left arrow, RANDOM begin block, 1 comma 3, end block Begin block Line 2: IF, begin block, spin equals 1, end block Begin block Line 3, indented 1 tab: RETURN, begin block, quotation mark, Red, quotation mark, end block End block End block Begin block Line 4: IF, begin block, spin equals 2, end block Begin block Line 5, indented 1 tab: RETURN, begin block, quotation mark, Yellow, quotation mark, end block End block End block Line 6: RETURN, begin block, quotation mark, Blue, quotation mark, end block
Option B,Image with alt text: The block code consists of 6 lines. Line 1: spin, left arrow, RANDOM begin block, 1 comma 3, end block Begin block Line 2: IF, begin block, spin equals 1, end block Begin block Line 3, indented 1 tab: RETURN, begin block, quotation mark, Yellow, quotation mark, end block End block End block Begin block Line 4: IF, begin block, spin equals 2, end block Begin block Line 5, indented 1 tab: RETURN, begin block, quotation mark, Blue, quotation mark, end block End block End block Line 6: RETURN, begin block, quotation mark, Red, quotation mark, end block
Option C,Image with alt text: The block code consists of 6 lines. Line 1: spin, left arrow, RANDOM begin block, 1 comma 6, end block Begin block Line 2: IF, begin block, spin equals 1, end block Begin block Line 3, indented 1 tab: RETURN, begin block, quotation mark, Red, quotation mark, end block End block End block Begin block Line 4: IF, begin block, spin equals 2, end block Begin block Line 5, indented 1 tab: RETURN, begin block, quotation mark, Yellow, quotation mark, end block End block End block Line 6: RETURN, begin block, quotation mark, Blue, quotation mark, end block
Option D,Image with alt text: The block code consists of 6 lines. Line 1: spin, left arrow, RANDOM begin block, 1 comma 6, end block Begin block Line 2: IF, begin block, spin equals 1, end block Begin block Line 3, indented 1 tab: RETURN, begin block, quotation mark, Yellow, quotation mark, end block End block End block Begin block Line 4: IF, begin block, spin equals 2, end block Begin block Line 5, indented 1 tab: RETURN, begin block, quotation mark, Blue, quotation mark, end block End block End block Line 6: RETURN, begin block, quotation mark, Red, quotation mark, end block
Question
The procedure below is intended to simulate the behavior of the spinner.
Question
11
Mark for Review
Which of the following can be used to replace so that the procedure correctly simulates the spinner?
Option A,Image with alt text: The block code consists of 6 lines. Line 1: spin, left arrow, RANDOM begin block, 1 comma 3, end block Begin block Line 2: IF, begin block, spin equals 1, end block Begin block Line 3, indented 1 tab: RETURN, begin block, quotation mark, Red, quotation mark, end block End block End block Begin block Line 4: IF, begin block, spin equals 2, end block Begin block Line 5, indented 1 tab: RETURN, begin block, quotation mark, Yellow, quotation mark, end block End block End block Line 6: RETURN, begin block, quotation mark, Blue, quotation mark, end block
Option B,Image with alt text: The block code consists of 6 lines. Line 1: spin, left arrow, RANDOM begin block, 1 comma 3, end block Begin block Line 2: IF, begin block, spin equals 1, end block Begin block Line 3, indented 1 tab: RETURN, begin block, quotation mark, Yellow, quotation mark, end block End block End block Begin block Line 4: IF, begin block, spin equals 2, end block Begin block Line 5, indented 1 tab: RETURN, begin block, quotation mark, Blue, quotation mark, end block End block End block Line 6: RETURN, begin block, quotation mark, Red, quotation mark, end block
Option C,Image with alt text: The block code consists of 6 lines. Line 1: spin, left arrow, RANDOM begin block, 1 comma 6, end block Begin block Line 2: IF, begin block, spin equals 1, end block Begin block Line 3, indented 1 tab: RETURN, begin block, quotation mark, Red, quotation mark, end block End block End block Begin block Line 4: IF, begin block, spin equals 2, end block Begin block Line 5, indented 1 tab: RETURN, begin block, quotation mark, Yellow, quotation mark, end block End block End block Line 6: RETURN, begin block, quotation mark, Blue, quotation mark, end block
Option D,Image with alt text: The block code consists of 6 lines. Line 1: spin, left arrow, RANDOM begin block, 1 comma 6, end block Begin block Line 2: IF, begin block, spin equals 1, end block Begin block Line 3, indented 1 tab: RETURN, begin block, quotation mark, Yellow, quotation mark, end block End block End block Begin block Line 4: IF, begin block, spin equals 2, end block Begin block Line 5, indented 1 tab: RETURN, begin block, quotation mark, Blue, quotation mark, end block End block End block Line 6: RETURN, begin block, quotation mark, Red, quotation mark, end block
Question
Answers
GPT-4o mini
To determine which option can be used to simulate the behavior of the spinner correctly, we need to analyze the setup of the spinner:
1. The spinner has three sections:
- One section is "four times" as large as each of the other two equal sections.
This means that if we denote the size of each of the smaller sections as \( x \), then the larger section must be \( 4x \).
As a result, we can state the following proportions:
- Total sections = \( x + x + 4x = 6x \)
- Probability of landing on each section:
- The larger section: \( \frac{4x}{6x} = \frac{2}{3} \)
- Each of the smaller sections: \( \frac{x}{6x} = \frac{1}{6} \)
This indicates that the spinner sections should be represented proportionally in the code that simulates the spinner's behavior:
- Larger section (let's say "Red") should have a higher probability of being chosen.
- The two smaller, equal sections (let's say "Yellow" and "Blue") should each have a lower probability.
**Analyzing the Options:**
- **Option A**:
- `RANDOM 1 to 3` means there are three distinct options. Thus, it can’t represent the correct ratios for three sections with one being larger than the others.
- **Option B**:
- `RANDOM 1 to 3` is also present here, which does the same as Option A.
- **Option C**:
- `RANDOM 1 to 6` ensures that there are enough slots for the different probabilities, where two slots could correspond to "Red", and one each for "Yellow" and "Blue".
- This seems feasible as it accounts for the larger section's greater probability.
- **Option D**:
- Similar to Option C, it also uses `RANDOM 1 to 6`, but the allocation doesn’t align properly with the intended probabilities.
Based on these considerations, **Option C** can be used to effectively simulate the spinner's behavior in a way that reflects the dimensions of the spinner sections correctly.
Answer: **Option C** would be the correct choice.
1. The spinner has three sections:
- One section is "four times" as large as each of the other two equal sections.
This means that if we denote the size of each of the smaller sections as \( x \), then the larger section must be \( 4x \).
As a result, we can state the following proportions:
- Total sections = \( x + x + 4x = 6x \)
- Probability of landing on each section:
- The larger section: \( \frac{4x}{6x} = \frac{2}{3} \)
- Each of the smaller sections: \( \frac{x}{6x} = \frac{1}{6} \)
This indicates that the spinner sections should be represented proportionally in the code that simulates the spinner's behavior:
- Larger section (let's say "Red") should have a higher probability of being chosen.
- The two smaller, equal sections (let's say "Yellow" and "Blue") should each have a lower probability.
**Analyzing the Options:**
- **Option A**:
- `RANDOM 1 to 3` means there are three distinct options. Thus, it can’t represent the correct ratios for three sections with one being larger than the others.
- **Option B**:
- `RANDOM 1 to 3` is also present here, which does the same as Option A.
- **Option C**:
- `RANDOM 1 to 6` ensures that there are enough slots for the different probabilities, where two slots could correspond to "Red", and one each for "Yellow" and "Blue".
- This seems feasible as it accounts for the larger section's greater probability.
- **Option D**:
- Similar to Option C, it also uses `RANDOM 1 to 6`, but the allocation doesn’t align properly with the intended probabilities.
Based on these considerations, **Option C** can be used to effectively simulate the spinner's behavior in a way that reflects the dimensions of the spinner sections correctly.
Answer: **Option C** would be the correct choice.