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Carlos has built a snowman consisting solely of 3 spherical snowballs. The bottom snowball has a radius of 3 ft, the middle sno...Asked by nagumo
Carlos has built a snowman consisting solely of 3 spherical snowballs.
The bottom snowball has a radius of 3 ft, the middle snowball has a radius of 2 ft, and the top snowball has a radius of 1 ft.
What is the total volume of the snowman?
(1 point)
Responses
288π ft3
288π ft3
48π ft3
48π ft3
36π ft3
36π ft3
216π ft3
The bottom snowball has a radius of 3 ft, the middle snowball has a radius of 2 ft, and the top snowball has a radius of 1 ft.
What is the total volume of the snowman?
(1 point)
Responses
288π ft3
288π ft3
48π ft3
48π ft3
36π ft3
36π ft3
216π ft3
Answers
Answered by
GPT-4o mini
To find the total volume of the snowman made of three spherical snowballs, we need to calculate the volume of each snowball and then sum the volumes. The formula for the volume \( V \) of a sphere is given by:
\[
V = \frac{4}{3} \pi r^3
\]
where \( r \) is the radius of the sphere.
1. **Volume of the bottom snowball (radius = 3 ft):**
\[
V_1 = \frac{4}{3} \pi (3)^3 = \frac{4}{3} \pi \times 27 = 36 \pi \text{ ft}^3
\]
2. **Volume of the middle snowball (radius = 2 ft):**
\[
V_2 = \frac{4}{3} \pi (2)^3 = \frac{4}{3} \pi \times 8 = \frac{32}{3} \pi \text{ ft}^3
\]
3. **Volume of the top snowball (radius = 1 ft):**
\[
V_3 = \frac{4}{3} \pi (1)^3 = \frac{4}{3} \pi \times 1 = \frac{4}{3} \pi \text{ ft}^3
\]
Now, we sum the volumes of all three snowballs:
\[
V_{total} = V_1 + V_2 + V_3 = 36\pi + \frac{32}{3}\pi + \frac{4}{3}\pi
\]
First, we convert \( 36\pi \) to have a common denominator of 3:
\[
36\pi = \frac{108}{3}\pi
\]
Now, we can sum the volumes:
\[
V_{total} = \frac{108}{3}\pi + \frac{32}{3}\pi + \frac{4}{3}\pi = \frac{108 + 32 + 4}{3}\pi = \frac{144}{3}\pi = 48\pi \text{ ft}^3
\]
Thus, the total volume of the snowman is:
\[
\boxed{48\pi \text{ ft}^3}
\]
\[
V = \frac{4}{3} \pi r^3
\]
where \( r \) is the radius of the sphere.
1. **Volume of the bottom snowball (radius = 3 ft):**
\[
V_1 = \frac{4}{3} \pi (3)^3 = \frac{4}{3} \pi \times 27 = 36 \pi \text{ ft}^3
\]
2. **Volume of the middle snowball (radius = 2 ft):**
\[
V_2 = \frac{4}{3} \pi (2)^3 = \frac{4}{3} \pi \times 8 = \frac{32}{3} \pi \text{ ft}^3
\]
3. **Volume of the top snowball (radius = 1 ft):**
\[
V_3 = \frac{4}{3} \pi (1)^3 = \frac{4}{3} \pi \times 1 = \frac{4}{3} \pi \text{ ft}^3
\]
Now, we sum the volumes of all three snowballs:
\[
V_{total} = V_1 + V_2 + V_3 = 36\pi + \frac{32}{3}\pi + \frac{4}{3}\pi
\]
First, we convert \( 36\pi \) to have a common denominator of 3:
\[
36\pi = \frac{108}{3}\pi
\]
Now, we can sum the volumes:
\[
V_{total} = \frac{108}{3}\pi + \frac{32}{3}\pi + \frac{4}{3}\pi = \frac{108 + 32 + 4}{3}\pi = \frac{144}{3}\pi = 48\pi \text{ ft}^3
\]
Thus, the total volume of the snowman is:
\[
\boxed{48\pi \text{ ft}^3}
\]
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