To determine the height of the can, we can use the formula for the volume of a cylinder:
\[ V = \pi r^2 h \]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height.
We are given:
- \( V = 450 \) cubic inches,
- The diameter of the can is 4 inches, which means the radius \( r \) is \( \frac{4}{2} = 2 \) inches.
Now we can plug in the values into the volume formula and solve for \( h \):
\[ 450 = \pi (2)^2 h \]
This simplifies to:
\[ 450 = \pi (4) h \]
\[ 450 = 4\pi h \]
Now, we can solve for \( h \):
\[ h = \frac{450}{4\pi} \]
Calculating \( h \):
\[ h = \frac{450}{4 \times 3.14159} \approx \frac{450}{12.56636} \approx 35.8 \]
So, the height of the can, to the nearest tenth of an inch, is \( 35.8 \) inches.
The correct response is:
35.8 in