Use the formula for the volume of a rectangular pyramid to find the volume of a pyramid-shaped tent whose height is 75 in., width is 111 in., and length is 111 in. when standing.(1 point)

Responses

400,000 in.3
400,000 in. cubed

308,025 in.3
308,025 in. cubed

924,075 in.3
924,075 in. cubed

33,034.03 in.3

1 answer

To find the volume of a rectangular pyramid, you can use the formula:

\[ V = \frac{1}{3} \times \text{base area} \times \text{height} \]

The base area of the pyramid can be calculated using the formula:

\[ \text{base area} = \text{length} \times \text{width} \]

In this case, the dimensions of the pyramid-shaped tent are:

  • Height (h) = 75 in.
  • Width (w) = 111 in.
  • Length (l) = 111 in.

First, calculate the base area:

\[ \text{base area} = 111 , \text{in.} \times 111 , \text{in.} = 12,321 , \text{in.}^2 \]

Now, substitute the base area and height into the volume formula:

\[ V = \frac{1}{3} \times 12,321 , \text{in.}^2 \times 75 , \text{in.} \]

Now calculate the volume:

\[ V = \frac{1}{3} \times 12,321 \times 75 = \frac{924,075}{3} = 308,025 , \text{in.}^3 \]

Therefore, the volume of the pyramid-shaped tent is:

308,025 in.³ (also written as 308,025 in. cubed).