To find the volume of a rectangular pyramid, you can use the formula:
\[ \text{Volume} = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]
In this case, the base of the pyramid is a square with a side length of 12 meters. Therefore, the area of the base is:
\[ \text{Base Area} = \text{Side Length}^2 = 12 , \text{m} \times 12 , \text{m} = 144 , \text{m}^2 \]
The height of the pyramid is given as 10 meters. Substituting the base area and height into the volume formula gives:
\[ \text{Volume} = \frac{1}{3} \times 144 , \text{m}^2 \times 10 , \text{m} = \frac{1}{3} \times 1440 , \text{m}^3 = 480 , \text{m}^3 \]
Thus, the volume of the rectangular pyramid is:
\[ \boxed{480 , \text{m}^3} \]