To solve the system of equations:
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\(-5x + 4y = 48\) (Equation 1)
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\(-5x - 8y = 24\) (Equation 2)
We can solve this system using the elimination method or substitution. Here, I will use elimination.
First, let's eliminate \( -5x \) by subtracting Equation 2 from Equation 1.
Subtract Equation 2 from Equation 1:
\[ (-5x + 4y) - (-5x - 8y) = 48 - 24 \]
This simplifies to:
\[ 4y + 8y = 48 - 24 \]
Combining the \(y\) terms gives:
\[ 12y = 24 \]
Now, divide both sides by 12:
\[ y = 2 \]
Now that we have \(y\), we substitute \(y = 2\) back into either Equation 1 or Equation 2 to find \(x\). Let's use Equation 1:
\[ -5x + 4(2) = 48 \]
This simplifies to:
\[ -5x + 8 = 48 \]
Subtract 8 from both sides:
\[ -5x = 40 \]
Now, divide by -5:
\[ x = -8 \]
So, the solution to the system of equations is:
\((-8, 2)\)
Thus, the answer is \((−8, 2)\).