To solve the system of equations given by:
- \( x - 3y = 18 \) (Equation 1)
- \( 7x - 5y = 46 \) (Equation 2)
We will use the substitution method. First, we will solve Equation 1 for \( x \):
\[ x = 3y + 18 \]
Now we can substitute this expression for \( x \) into Equation 2:
\[ 7(3y + 18) - 5y = 46 \]
Distributing the 7:
\[ 21y + 126 - 5y = 46 \]
Combine like terms:
\[ 16y + 126 = 46 \]
Now, isolate \( y \):
\[ 16y = 46 - 126 \] \[ 16y = -80 \] \[ y = -5 \]
Now that we have \( y \), we can substitute it back into the expression we found for \( x \):
\[ x = 3(-5) + 18 \] \[ x = -15 + 18 \] \[ x = 3 \]
So the solution to the system of equations is \( (3, -5) \).
The correct response is:
(3, −5)