To determine which graph correctly represents the system of equations \( y = 3x + 4 \) and \( -3x + y = 8 \) with no solution, we first need to analyze the equations.
- The first equation \( y = 3x + 4 \) has a slope of 3 and a y-intercept at (0, 4).
- The second equation can be rewritten as \( y = 3x + 8 \) (by adding \( 3x \) to both sides), which also has a slope of 3 but a different y-intercept at (0, 8).
Since both lines have the same slope (3) but different y-intercepts (4 and 8), they are parallel lines. Parallel lines never intersect, which means the system of equations has no solution.
Now, we look for a graph where there are two parallel lines with the characteristics described.
From your descriptions of the graphs:
- Graph 1: One line passes through (0, 4) and (−3, −5) (which has a slope of 3) and the other line passes through (0, 8) and (−4, −4) (also has a slope of 3). These lines are parallel.
- Graph 2, 3, and 4: The descriptions do not indicate that the lines have the necessary parallel characteristics of having the same slope.
Thus, Graph 1 is the only one that shows a system of equations that has no solution since it displays two parallel lines correctly corresponding to \( y = 3x + 4 \) and \( y = 3x + 8 \).
Therefore, the answer is Graph 1.