Triangle ABC has vertices point A(−2,−2) , point B(−4,−3) , and point C(−2,−5) . Find the coordinates of A′ , B′ , and C′ after a dilation with a scale factor of 3 and a center point of dilation at the origin.(2 points)

A′= (__,__) B′= (__,__) C′= (__,__)

1 answer

To find the coordinates of the points after a dilation with a scale factor of 3 from the origin, we can use the formula for dilation. Given a point \((x, y)\) and a scale factor \(k\), the new coordinates \((x', y')\) after dilation are given by:

\[ x' = k \cdot x \] \[ y' = k \cdot y \]

In this case, the scale factor \(k = 3\).

Now applying this to each vertex:

  1. For point \(A(-2, -2)\): \[ A' = (3 \cdot -2, 3 \cdot -2) = (-6, -6) \]

  2. For point \(B(-4, -3)\): \[ B' = (3 \cdot -4, 3 \cdot -3) = (-12, -9) \]

  3. For point \(C(-2, -5)\): \[ C' = (3 \cdot -2, 3 \cdot -5) = (-6, -15) \]

After calculating all points, we find:

  • \(A' = (-6, -6)\)
  • \(B' = (-12, -9)\)
  • \(C' = (-6, -15)\)

Thus, the final coordinates after dilation are:

  • A′ = (-6, -6)
  • B′ = (-12, -9)
  • C′ = (-6, -15)