How do I work this to get the answer because I am stuck. Help, Help, please anyone. Ihope that you are able to understand what I am asking.
3 SQRT10 over SQRT15
2 over 5+SQRT3
2 answers
You have to get the square roots out of the denominator by multipling the top and bottom by (for the first on) the SQRT15. And the second one by (5-SQRT3). Then you should be able to simplify. I hope that helps a little!
1. 3 sqrt10 / sqrt15 =
Multiply numerator and denominator by sqrt15:
3sqrt10*sqrt15 /15 = 3sqrt(10*15)/15 =
3sqrt(25*6) / 15 = 3*5sqrt(6) / 15 =
sqrt6. = 2.45
2. 2 / (5 + sqrt3) =
Multiply num. and den. by (5 - sqrt3)
2(5 - sqrt3) / (5 + sqrt3) (5 - sqrt3)
= (10 - 2sqrt3) / 22 = (5 - sqrt3) / 11
= 0.297
Multiply numerator and denominator by sqrt15:
3sqrt10*sqrt15 /15 = 3sqrt(10*15)/15 =
3sqrt(25*6) / 15 = 3*5sqrt(6) / 15 =
sqrt6. = 2.45
2. 2 / (5 + sqrt3) =
Multiply num. and den. by (5 - sqrt3)
2(5 - sqrt3) / (5 + sqrt3) (5 - sqrt3)
= (10 - 2sqrt3) / 22 = (5 - sqrt3) / 11
= 0.297
2 answers