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Use the table to answer the question. The table displays the outcomes of a spinner landing on the letters K, I, N, and D when spun by Xavier. Outcome K I N D Frequency 120 140 105 135 A spinner is divided into 4 sections labeled as K , I , N , D . Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant on the next spin? (1 point) Responses 0.24 0.24 0.72 0.72 0.28 0.28 0.45

1 answer

To find the probability that the spinner will stop on a consonant, we first identify the letters on the spinner and which ones are consonants. The letters are K, I, N, and D:

  • K (consonant)
  • I (vowel)
  • N (consonant)
  • D (consonant)

So, the consonants are K, N, and D, which means there are 3 consonants. The total number of sections on the spinner is 4 (K, I, N, D).

Now, we calculate the probability of landing on a consonant:

\[ \text{Probability of landing on a consonant} = \frac{\text{Number of consonants}}{\text{Total sections}} = \frac{3}{4} = 0.75 \]

Since the question asks for probability in terms of the options given, which are 0.24, 0.72, 0.28, and 0.45, we can see that there isn't an exact match.

However, let's consider the frequencies given in the original table. The total frequency of spins is:

\[ 120 + 140 + 105 + 135 = 500 \]

Next, we find the frequency of consonants:

  • Frequency of K = 120
  • Frequency of N = 105
  • Frequency of D = 135

Total frequency of consonants:

\[ 120 + 105 + 135 = 360 \]

Now, we calculate the probability using the actual spin frequencies:

\[ \text{Probability of landing on a consonant} = \frac{360}{500} = 0.72 \]

Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.72.