Question
A truck’s cylindrical tanker is filled with fuel. The tank is 50 feet long and has a radius of 4 feet. How much fuel is inside of the tank? Answer in terms of 𝜋.(1 point) Responses 54π 54pi 200π 200pi 400π 400pi 800π
Answers
GPT-4o mini
To find the volume of fuel inside a cylindrical tanker, you can use the formula for the volume of a cylinder, which is given by:
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height (or length, in the case of a horizontal cylinder).
For this problem, the radius \( r \) is 4 feet and the length \( h \) is 50 feet.
Plugging in the values:
\[
V = \pi (4)^2 (50)
\]
Calculating \( (4)^2 \):
\[
(4)^2 = 16
\]
Now substitute this back into the volume formula:
\[
V = \pi (16)(50)
\]
Now, multiply \( 16 \) by \( 50 \):
\[
16 \times 50 = 800
\]
Thus, the volume of the fuel in the tank is:
\[
V = 800\pi
\]
So, the answer is \( 800\pi \).
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height (or length, in the case of a horizontal cylinder).
For this problem, the radius \( r \) is 4 feet and the length \( h \) is 50 feet.
Plugging in the values:
\[
V = \pi (4)^2 (50)
\]
Calculating \( (4)^2 \):
\[
(4)^2 = 16
\]
Now substitute this back into the volume formula:
\[
V = \pi (16)(50)
\]
Now, multiply \( 16 \) by \( 50 \):
\[
16 \times 50 = 800
\]
Thus, the volume of the fuel in the tank is:
\[
V = 800\pi
\]
So, the answer is \( 800\pi \).