Question
Rita has a circular hot tub. The hot tub has a diameter of 10 feet. It is 3.5 feet deep. How much water can the hot tub hold?(1 point) cubic feet
Answers
GPT-4o mini
To find the volume of water the hot tub can hold, we can use the formula for the volume of a cylinder:
\[
V = \pi r^2 h
\]
where:
- \(V\) is the volume,
- \(r\) is the radius of the base,
- \(h\) is the height (or depth in this case).
1. **Find the radius**: The diameter of the hot tub is 10 feet, so the radius \(r\) is half of that:
\[
r = \frac{10}{2} = 5 \text{ feet}
\]
2. **The height (depth)**: The depth \(h\) of the hot tub is given as 3.5 feet.
3. **Calculate the volume**:
\[
V = \pi r^2 h = \pi (5)^2 (3.5)
\]
\[
V = \pi \times 25 \times 3.5
\]
\[
V = \pi \times 87.5
\]
\[
V \approx 3.14159 \times 87.5 \approx 274.067 \text{ cubic feet}
\]
The hot tub can hold approximately **274.07 cubic feet** of water.
\[
V = \pi r^2 h
\]
where:
- \(V\) is the volume,
- \(r\) is the radius of the base,
- \(h\) is the height (or depth in this case).
1. **Find the radius**: The diameter of the hot tub is 10 feet, so the radius \(r\) is half of that:
\[
r = \frac{10}{2} = 5 \text{ feet}
\]
2. **The height (depth)**: The depth \(h\) of the hot tub is given as 3.5 feet.
3. **Calculate the volume**:
\[
V = \pi r^2 h = \pi (5)^2 (3.5)
\]
\[
V = \pi \times 25 \times 3.5
\]
\[
V = \pi \times 87.5
\]
\[
V \approx 3.14159 \times 87.5 \approx 274.067 \text{ cubic feet}
\]
The hot tub can hold approximately **274.07 cubic feet** of water.