Question

What is the area of a parallelogram with a base of 7in. and a height of 8in. ?(1 point) Responses 56 sq. in. 56 sq. in. 15 sq. in. 15 sq. in. 28 sq. in. 28 sq. in. 49 sq. in. 49 sq. in. Question 4 What is the area of triangle with a base of 8cm and height of 4cm?(1 point) Responses 6 sq. cm. 6 sq. cm. 12 sq. cm. 12 sq. cm. 32 sq. cm. 32 sq. cm. 16 sq. cm. 16 sq. cm. Question 5 What is the area of a rectangle with a length of 16cm and a width of 18cm?(1 point) Responses 34 sq. cm 34 sq. cm 288 sq. cm 288 sq. cm 68 sq. cm 68 sq. cm 188 sq. cm

Answer 1

Let's calculate the areas of the shapes one by one:

**For the parallelogram:**
The formula for the area of a parallelogram is:
\[ \text{Area} = \text{base} \times \text{height} \]

Given:
- Base = 7 in
- Height = 8 in

So,
\[ \text{Area} = 7 \times 8 = 56 \text{ sq. in.} \]

**For the triangle:**
The formula for the area of a triangle is:
\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \]

Given:
- Base = 8 cm
- Height = 4 cm

So,
\[ \text{Area} = \frac{1}{2} \times 8 \times 4 = 16 \text{ sq. cm.} \]

**For the rectangle:**
The formula for the area of a rectangle is:
\[ \text{Area} = \text{length} \times \text{width} \]

Given:
- Length = 16 cm
- Width = 18 cm

So,
\[ \text{Area} = 16 \times 18 = 288 \text{ sq. cm.} \]

### Summary of Answers:
1. The area of the parallelogram is **56 sq. in.**
2. The area of the triangle is **16 sq. cm.**
3. The area of the rectangle is **288 sq. cm.**