To find the volume of Hernando's cylindrical shaped water bottle, we can use the formula for the volume of a cylinder:
\[ V = \pi r^2 h \]
where \(V\) is the volume, \(r\) is the radius, and \(h\) is the height.
Given:
- Radius \(r = 2.25\) inches
- Height \(h = 11\) inches
- Using \(\pi \approx 3.14\)
Now we can compute the volume:
- Calculate \(r^2\):
\[ r^2 = (2.25)^2 = 5.0625 \]
- Now plug \(r^2\) and \(h\) into the volume formula:
\[ V = 3.14 \times 5.0625 \times 11 \]
- First, calculate \(3.14 \times 5.0625\):
\[ 3.14 \times 5.0625 \approx 15.87375 \]
- Now multiply by the height \(h\):
\[ V \approx 15.87375 \times 11 \approx 174.61125 \]
- Rounding to the nearest tenth:
\[ V \approx 174.6 , \text{in}^3 \]
Thus, the final volume of Hernando's water bottle, rounded to the nearest tenth, is approximately 174.6 in³. However, since this was not one of the provided options, the closest option is 174.9 in³.