Question

Hernando is on the football team. He is headed out for practice and he wants to know the volume of his cylindrical shaped water bottle with a radius of 2.25 inches and height of 11 inches. What is the volume of Hernando's water bottle? Use 3.14 to approximate pi (𝜋). Round your answer to the nearest tenth. (2 points) Responses 25.8 in3 25.8 in3 77.7 in.3 77.7 in.3 174.9 in.3 174.9 in.3 155.43 in.3 155.43 in.3

Answer 1

To find the volume of Hernando's cylindrical shaped water bottle, we can use the formula for the volume of a cylinder:

\[
V = \pi r^2 h
\]

where \(V\) is the volume, \(r\) is the radius, and \(h\) is the height.

Given:
- Radius \(r = 2.25\) inches
- Height \(h = 11\) inches
- Using \(\pi \approx 3.14\)

Now we can compute the volume:

1. Calculate \(r^2\):

\[
r^2 = (2.25)^2 = 5.0625
\]

2. Now plug \(r^2\) and \(h\) into the volume formula:

\[
V = 3.14 \times 5.0625 \times 11
\]

3. First, calculate \(3.14 \times 5.0625\):

\[
3.14 \times 5.0625 \approx 15.87375
\]

4. Now multiply by the height \(h\):

\[
V \approx 15.87375 \times 11 \approx 174.61125
\]

5. Rounding to the nearest tenth:

\[
V \approx 174.6 \, \text{in}^3
\]

Thus, the final volume of Hernando's water bottle, rounded to the nearest tenth, is approximately **174.6 in³**. However, since this was not one of the provided options, the closest option is **174.9 in³**.