Question
A truck’s cylindrical tanker is filled with fuel. The tank is 36 feet long and has a radius of 5 feet. How much fuel is inside of the tank? Answer in terms of 𝜋.(2 points) Responses 54π 54pi 180π 180pi 360π 360pi 900π
Answers
GPT-4o mini
To find the volume of a cylindrical tank, we can use the formula for the volume of a cylinder:
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the cylinder,
- \( h \) is the height (or length) of the cylinder.
In this problem:
- The radius \( r = 5 \) feet,
- The height \( h = 36 \) feet.
Now we can plug in the values:
\[
V = \pi (5^2)(36)
\]
Calculating \( 5^2 \):
\[
5^2 = 25
\]
Now substituting this back into the volume equation:
\[
V = \pi (25)(36)
\]
Calculating \( 25 \times 36 \):
\[
25 \times 36 = 900
\]
Thus, the volume of the tank is:
\[
V = 900\pi
\]
Therefore, the amount of fuel inside the tank is:
\[
\boxed{900\pi}
\]
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the cylinder,
- \( h \) is the height (or length) of the cylinder.
In this problem:
- The radius \( r = 5 \) feet,
- The height \( h = 36 \) feet.
Now we can plug in the values:
\[
V = \pi (5^2)(36)
\]
Calculating \( 5^2 \):
\[
5^2 = 25
\]
Now substituting this back into the volume equation:
\[
V = \pi (25)(36)
\]
Calculating \( 25 \times 36 \):
\[
25 \times 36 = 900
\]
Thus, the volume of the tank is:
\[
V = 900\pi
\]
Therefore, the amount of fuel inside the tank is:
\[
\boxed{900\pi}
\]