Use the table to answer the question.

Compound Event Total Number of Occurrences
Heads and Yellow 9
Heads and Red 3
Heads and Blue 4
Heads and Green 1
Tails and Yellow 6
Tails and Red 7
Tails and Blue 2
Tails and Green 3
A student had a spinner and a coin. The student was running an experiment for math class. The spinner had an equal chance of landing on 4 colors: yellow, red, blue, and green. The student flipped the coin and spun the spinner, and the results are recorded in the table.

If the student were to flip the coin and spin the spinner 130 times, how many times would the result be tails and red?

(1 point)
Responses

11 times
11 times

22 times
22 times

26 times
26 times

35 times

1 answer

To determine how many times the student would result in "tails and red" if they flipped the coin and spun the spinner 130 times, we can use the data provided in the table.

From the table, we see the total number of occurrences of "tails and red" is 7.

Next, we calculate the total number of occurrences of all compound events provided in the table:

  • Heads and Yellow: 9
  • Heads and Red: 3
  • Heads and Blue: 4
  • Heads and Green: 1
  • Tails and Yellow: 6
  • Tails and Red: 7
  • Tails and Blue: 2
  • Tails and Green: 3

Now, we add these occurrences together:

\[ 9 + 3 + 4 + 1 + 6 + 7 + 2 + 3 = 35 \]

There are 35 total occurrences of all events recorded in the table.

To find out how often "tails and red" would occur in 130 trials, we can set up a ratio:

\[ \text{Probability of tails and red} = \frac{\text{Occurrences of tails and red}}{\text{Total occurrences}} = \frac{7}{35} \]

Now we calculate this probability:

\[ \frac{7}{35} = \frac{1}{5} \]

Now, to find out how many times tails and red would occur in 130 trials, we multiply the total trials (130) by this probability:

\[ 130 \times \frac{1}{5} = 26 \]

So, if the student were to flip the coin and spin the spinner 130 times, the expected number of times the result would be tails and red is 26 times.

Therefore, the correct answer is:

26 times