To find the volume of the composite figure, we will calculate the volumes of both the cubes and the cuboid separately and then add them together.
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Volume of the cubes: Each cube has a side length of 5 cm. The volume \( V \) of a cube is given by the formula: \[ V = s^3 \] where \( s \) is the side length. So for one cube: \[ V = 5^3 = 125 , \text{cm}^3 \] Since there are two cubes: \[ V_{\text{cubes}} = 2 \times 125 = 250 , \text{cm}^3 \]
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Volume of the cuboid: The cuboid has a length of 10 cm, width of 5 cm (equal to the side of the cubes), and height of 12 cm. The volume \( V \) of a cuboid is given by the formula: \[ V = l \times w \times h \] Substituting the values: \[ V = 10 , \text{cm} \times 5 , \text{cm} \times 12 , \text{cm} = 600 , \text{cm}^3 \]
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Total volume of the composite figure: We now combine the volume of the cubes and the cuboid: \[ V_{\text{total}} = V_{\text{cubes}} + V_{\text{cuboid}} = 250 , \text{cm}^3 + 600 , \text{cm}^3 = 850 , \text{cm}^3 \]
Thus, the volume of the composite figure is \( \boxed{850 , \text{cm}^3} \).