To find the other dimension of the pyramid's base, we can use the formula for the volume of a rectangular pyramid:
\[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]
Where the Base Area \(A\) of a rectangle is given by:
\[ A = \text{length} \times \text{width} \]
In this case, we know:
- Volume \(V = 22,750 , \text{cm}^3\)
- Length = 30 cm
- Height = 65 cm
Let's denote the width as \(w\). Then the Base Area can be expressed as:
\[ A = 30 \times w \]
Substituting the Volume formula gives us:
\[ 22,750 = \frac{1}{3} \times (30 \times w) \times 65 \]
Now, simplify this equation step by step:
- Multiply both sides by 3 to eliminate the fraction:
\[ 22,750 \times 3 = 30 \times w \times 65 \]
\[ 68,250 = 30 \times w \times 65 \]
- Calculate \(30 \times 65\):
\[ 30 \times 65 = 1950 \]
- Now, substitute \(1950\) back into the equation:
\[ 68,250 = 1950 \times w \]
- Solve for \(w\):
\[ w = \frac{68,250}{1950} \]
- Calculating the division:
\[ w = 35 \]
Therefore, the other dimension of the pyramid’s base is 35 cm.
So the correct answer is:
35 cm