What is the volume of a moving truck with the following measurements: 9 9/10

ft. long, 6 1/10
ft. high, and 6 9/10
ft. wide? Apply the volume formula for a rectangular prism to solve. (1 point)
Responses

691 416/1,000ft.3
691 start fraction 416 over 1,000 end fraction ft cubed

416 691/1,000ft.3
416 start fraction 691 over 1,000 end fraction ft cubed

22 9/10ft.3
22 start fraction 9 over 10 end fraction ft cubed

68 31/100ft.3
68 start fraction 31 over 100 end fraction ft cubed

1 answer

To find the volume of the moving truck, we can use the formula for the volume of a rectangular prism, which is:

\[ \text{Volume} = \text{length} \times \text{width} \times \text{height} \]

Given measurements:

  • Length = \( 9 \frac{9}{10} \) ft = \( 9.9 \) ft,
  • Height = \( 6 \frac{1}{10} \) ft = \( 6.1 \) ft,
  • Width = \( 6 \frac{9}{10} \) ft = \( 6.9 \) ft.

Now we will calculate the volume:

\[ \text{Volume} = 9.9 \times 6.1 \times 6.9 \]

Calculating step by step:

  1. \( 9.9 \times 6.1 = 60.39 \)
  2. Now multiply this result by \( 6.9 \):

\[ 60.39 \times 6.9 = 416.691 \]

Thus, the total volume of the moving truck is \( 416.691 \) ft³.

To express this as a fraction:

\[ 416.691 = 416 + 0.691 = 416 + \frac{691}{1000} \]

Therefore, it can be written as:

\[ 416 \frac{691}{1000} , \text{ft}^3 \]

The correct response is:

416 \( \frac{691}{1000} , \text{ft}^3 \)