To find the amperage (I) of the circuit, we first need to determine the total voltage supplied by the batteries. Since there are four 1.5-volt batteries, the total voltage (V) is calculated as follows:
\[ V = 4 \times 1.5 , \text{volts} = 6 , \text{volts} \]
Next, we can use Ohm's law, which is given by the formula:
\[ V = I \times R \]
We can rearrange this formula to solve for the current (I):
\[ I = \frac{V}{R} \]
Substituting the known values into the equation:
- Voltage (V) = 6 volts
- Resistance (R) = 2.4 ohms
Now we can calculate the current:
\[ I = \frac{6 , \text{volts}}{2.4 , \text{ohms}} = 2.5 , \text{A} \]
So, the amperage of the circuit is 2.5 A.