In a circle, the diameter is the longest chord. Points B and C are opposite each other on the circumference, meaning that segment BC is a diameter.
According to the triangle inequality theorem, for any triangle, the sum of the lengths of any two sides must be greater than the length of the remaining side. In this case, segments AB and AC are each radii of the circle.
Since \( AB \) and \( AC \) are both radii, and segment \( BC \) is a diameter, we can conclude that:
\[ AB + AC > BC. \]
Therefore, the correct inequality is:
AB + AC > BC.
So the answer is: > (greater than).