Question

Suppose a soup can has a diameter of 10 cm and a height of 12 cm. What is the volume of soup in the can? (to nearest whole number)
Responses
A 36
36 cm 3
B 48
48 cm 3
C 144
144 cm 3
D 942

Answer 1

To find the volume \( V \) of the soup can, which is in the shape of a cylinder, you can use the formula for the volume of a cylinder:

\[
V = \pi r^2 h
\]

where:
- \( r \) is the radius of the cylinder
- \( h \) is the height of the cylinder
- \( \pi \) is approximately 3.14159

Given:
- Diameter of the can = 10 cm, so the radius \( r \) = \frac{diameter}{2} = \frac{10}{2} = 5 \) cm
- Height \( h = 12 \) cm

Now, substitute the values into the formula:

\[
V = \pi (5)^2 (12)
\]
\[
V = \pi (25)(12)
\]
\[
V = 300\pi
\]

Now we calculate \( 300\pi \):

\[
V \approx 300 \times 3.14159 \approx 942.477
\]

Rounding this to the nearest whole number gives:

\[
V \approx 942 \, \text{cm}^3
\]

Thus, the answer is:

**D 942**