Let's analyze the linear equation given in the context of the scenario.
- End Behavior of the Graph: Since the equation of the line is \( x + 2y = 7 \), we can rewrite it in slope-intercept form (y = mx + b):
\[ 2y = -x + 7 \quad \Rightarrow \quad y = -\frac{1}{2}x + \frac{7}{2} \]
The slope is -1/2, indicating that as \( x \) increases (goes to +∞), \( y \) decreases (goes to -∞). Conversely, as \( x \) decreases (goes to -∞), \( y \) increases (goes to +∞). Thus, the end behavior is:
As \( x \) goes to -∞, \( y \) goes to +∞. As \( x \) goes to +∞, \( y \) goes to -∞.
- Reasonable Domain (Input): In the context of this scenario (chips in a bag over time), \( x \) represents time in minutes and \( y \) represents the amount of chips in ounces. Since you cannot have negative time or more than the total amount of chips in the bag, a reasonable domain is:
[0, 7] (since 7 minutes is the maximum time based on the graph).
- Reasonable Range (Outputs): The output \( y \) (the total amount of chips in ounces) changes as \( x \) varies. The maximum amount of chips occurs at when \( x = 0 \) (which is 3.5 ounces). The minimum occurs when \( x = 7 \) (which is 0 ounces). Therefore, a reasonable range for the scenario is:
[0, 3.5] (since 0 oz is the minimum and 3.5 oz is the maximum according to the graph).
Summary:
- End Behavior: As \( x \) goes to -∞, \( y \) goes to +∞. As \( x \) goes to +∞, \( y \) goes to -∞.
- Domain: [0, 7]
- Range: [0, 3.5]