To solve the problem, let's define the variables:
- Let \( s \) be the number of pounds of sunflower seeds.
- Let \( p \) be the number of pounds of pumpkin seeds.
Step 1: Write expressions for costs
-
Cost of sunflower seeds: \[ \text{Cost of } s \text{ pounds of sunflower seeds} = 0.75s \]
-
Cost of pumpkin seeds: \[ \text{Cost of } p \text{ pounds of pumpkin seeds} = 0.50p \]
Step 2: Combine the cost expressions
Combining these expressions gives: \[ 0.75s + 0.50p = \text{Total Cost} \]
Step 3: Set the equation equal to the total cost
From the problem, we know the total cost of the order is $13. Hence, we write: \[ 0.75s + 0.50p = 13 \]
Step 4: Set up the additional equation for weight
We also know the total weight of the seeds is 20 pounds, which gives us the second equation: \[ s + p = 20 \]
Summary of equations
Now we have a system of equations:
- \( 0.75s + 0.50p = 13 \)
- \( s + p = 20 \)
Step 5: Solve the system of equations
To solve, we can express \( p \) in terms of \( s \) from the second equation: \[ p = 20 - s \]
Now substitute \( p \) in the first equation: \[ 0.75s + 0.50(20 - s) = 13 \]
Distributing the 0.50: \[ 0.75s + 10 - 0.50s = 13 \]
Combine like terms: \[ 0.25s + 10 = 13 \]
Subtract 10 from both sides: \[ 0.25s = 3 \]
Divide by 0.25: \[ s = 12 \]
Now substitute \( s \) back to find \( p \): \[ p = 20 - s = 20 - 12 = 8 \]
Final Answer
The order contains:
- 12 pounds of sunflower seeds
- 8 pounds of pumpkin seeds