Question
Flour costs $0.75 per pound and sugar costs $0.50 per pound. An order of flour and sugar weighs 16 pounds and costs $9.
Next, solve this equation for the value of s.
0.75f+0.5s=9
f=16−s
0.75f+0.5s
=
9
0.75(16−s)+0.5s
=
9
s
=
Next, solve this equation for the value of s.
0.75f+0.5s=9
f=16−s
0.75f+0.5s
=
9
0.75(16−s)+0.5s
=
9
s
=
Answers
GPT-4o mini
We can solve the equation step by step.
Given the equations:
1. \( 0.75f + 0.5s = 9 \)
2. \( f = 16 - s \)
We substitute the second equation into the first equation:
\[
0.75(16 - s) + 0.5s = 9
\]
Now, let’s distribute \(0.75\):
\[
0.75 \times 16 - 0.75s + 0.5s = 9
\]
This simplifies to:
\[
12 - 0.75s + 0.5s = 9
\]
Combining like terms (\(-0.75s + 0.5s\)) gives us:
\[
12 - 0.25s = 9
\]
Next, we isolate the variable \(s\). First, subtract 12 from both sides:
\[
-0.25s = 9 - 12
\]
\[
-0.25s = -3
\]
Now, divide both sides by \(-0.25\):
\[
s = \frac{-3}{-0.25}
\]
This simplifies to:
\[
s = 12
\]
Thus, the value of \(s\) is \(12\).
Given the equations:
1. \( 0.75f + 0.5s = 9 \)
2. \( f = 16 - s \)
We substitute the second equation into the first equation:
\[
0.75(16 - s) + 0.5s = 9
\]
Now, let’s distribute \(0.75\):
\[
0.75 \times 16 - 0.75s + 0.5s = 9
\]
This simplifies to:
\[
12 - 0.75s + 0.5s = 9
\]
Combining like terms (\(-0.75s + 0.5s\)) gives us:
\[
12 - 0.25s = 9
\]
Next, we isolate the variable \(s\). First, subtract 12 from both sides:
\[
-0.25s = 9 - 12
\]
\[
-0.25s = -3
\]
Now, divide both sides by \(-0.25\):
\[
s = \frac{-3}{-0.25}
\]
This simplifies to:
\[
s = 12
\]
Thus, the value of \(s\) is \(12\).