To determine which dataset is less spread out, we need to calculate the mean absolute deviation (MAD) for each dataset.
Dataset #1: {51, 53, 56, 60, 72, 80}
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Compute the absolute deviations from the mean (which is 62):
- |51 - 62| = 11
- |53 - 62| = 9
- |56 - 62| = 6
- |60 - 62| = 2
- |72 - 62| = 10
- |80 - 62| = 18
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Sum the absolute deviations:
- 11 + 9 + 6 + 2 + 10 + 18 = 56
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Divide by the number of data points (6) to get the mean absolute deviation:
- MAD = 56 / 6 ≈ 9.3
Dataset #2: {49, 55, 61, 63, 70, 74}
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Compute the absolute deviations from the mean (which is 62):
- |49 - 62| = 13
- |55 - 62| = 7
- |61 - 62| = 1
- |63 - 62| = 1
- |70 - 62| = 8
- |74 - 62| = 12
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Sum the absolute deviations:
- 13 + 7 + 1 + 1 + 8 + 12 = 42
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Divide by the number of data points (6) to get the mean absolute deviation:
- MAD = 42 / 6 = 7.0
Comparison:
- Mean Absolute Deviation for Dataset #1: 9.3
- Mean Absolute Deviation for Dataset #2: 7.0
Since Dataset #2 has a lower mean absolute deviation (7.0) compared to Dataset #1 (9.3), this indicates that Dataset #2 is less spread out.
Therefore, the correct response is: Dataset #2 is less spread out because it has a mean absolute deviation of 7 whereas Dataset #1 has a mean absolute deviation of approximately 9.3.