Question
Lucia has been recording her grades on her Spanish quizzes. The following is a list of her grades:
74, 81, 86, 92, 74, 85, 90, 89, 78, 80
Determine the mean absolute deviation of Lucia’s Spanish quiz grades.
(1 point)
Responses
55
55
82.9
82.9
8.29
8.29
5.5
74, 81, 86, 92, 74, 85, 90, 89, 78, 80
Determine the mean absolute deviation of Lucia’s Spanish quiz grades.
(1 point)
Responses
55
55
82.9
82.9
8.29
8.29
5.5
Answers
GPT-4o mini
To calculate the mean absolute deviation (MAD) of Lucia's Spanish quiz grades, we follow these steps:
1. **Calculate the mean of the grades.**
The grades are: 74, 81, 86, 92, 74, 85, 90, 89, 78, 80.
First, find the sum of the grades:
\[
74 + 81 + 86 + 92 + 74 + 85 + 90 + 89 + 78 + 80 = 839
\]
Next, find the mean:
\[
\text{Mean} = \frac{839}{10} = 83.9
\]
2. **Calculate the absolute deviations from the mean.**
Now, we subtract the mean from each grade and take the absolute value:
- |74 - 83.9| = | -9.9| = 9.9
- |81 - 83.9| = | -2.9| = 2.9
- |86 - 83.9| = | 2.1| = 2.1
- |92 - 83.9| = | 8.1| = 8.1
- |74 - 83.9| = | -9.9| = 9.9
- |85 - 83.9| = | 1.1| = 1.1
- |90 - 83.9| = | 6.1| = 6.1
- |89 - 83.9| = | 5.1| = 5.1
- |78 - 83.9| = | -5.9| = 5.9
- |80 - 83.9| = | -3.9| = 3.9
The absolute deviations are:
9.9, 2.9, 2.1, 8.1, 9.9, 1.1, 6.1, 5.1, 5.9, 3.9
3. **Calculate the mean of these absolute deviations.**
Sum of absolute deviations:
\[
9.9 + 2.9 + 2.1 + 8.1 + 9.9 + 1.1 + 6.1 + 5.1 + 5.9 + 3.9 = 54.1
\]
Now, find the mean of these absolute deviations:
\[
\text{MAD} = \frac{54.1}{10} = 5.41
\]
Considering the options provided, none of the choices (55, 82.9, 8.29, 5.5) directly match the calculated 5.41.
However, since 5.41 is approximately equal to 5.5, the closest choice available is:
**5.5**
1. **Calculate the mean of the grades.**
The grades are: 74, 81, 86, 92, 74, 85, 90, 89, 78, 80.
First, find the sum of the grades:
\[
74 + 81 + 86 + 92 + 74 + 85 + 90 + 89 + 78 + 80 = 839
\]
Next, find the mean:
\[
\text{Mean} = \frac{839}{10} = 83.9
\]
2. **Calculate the absolute deviations from the mean.**
Now, we subtract the mean from each grade and take the absolute value:
- |74 - 83.9| = | -9.9| = 9.9
- |81 - 83.9| = | -2.9| = 2.9
- |86 - 83.9| = | 2.1| = 2.1
- |92 - 83.9| = | 8.1| = 8.1
- |74 - 83.9| = | -9.9| = 9.9
- |85 - 83.9| = | 1.1| = 1.1
- |90 - 83.9| = | 6.1| = 6.1
- |89 - 83.9| = | 5.1| = 5.1
- |78 - 83.9| = | -5.9| = 5.9
- |80 - 83.9| = | -3.9| = 3.9
The absolute deviations are:
9.9, 2.9, 2.1, 8.1, 9.9, 1.1, 6.1, 5.1, 5.9, 3.9
3. **Calculate the mean of these absolute deviations.**
Sum of absolute deviations:
\[
9.9 + 2.9 + 2.1 + 8.1 + 9.9 + 1.1 + 6.1 + 5.1 + 5.9 + 3.9 = 54.1
\]
Now, find the mean of these absolute deviations:
\[
\text{MAD} = \frac{54.1}{10} = 5.41
\]
Considering the options provided, none of the choices (55, 82.9, 8.29, 5.5) directly match the calculated 5.41.
However, since 5.41 is approximately equal to 5.5, the closest choice available is:
**5.5**