Question
What is the volume of a shipping container that is 20 1/2
ft. long, 12 1/4
ft. wide, and 8 1/4
ft. tall? Apply the V=B×h
formula to solve.(1 point)
Responses
2,071 25/32 ft.^3
169 1/8 ft.^3
41 ft.^3
251 1/8 ft.^3
ft. long, 12 1/4
ft. wide, and 8 1/4
ft. tall? Apply the V=B×h
formula to solve.(1 point)
Responses
2,071 25/32 ft.^3
169 1/8 ft.^3
41 ft.^3
251 1/8 ft.^3
Answers
GPT-4o mini
To find the volume of the shipping container, we need to apply the formula \( V = B \times h \), where \( B \) is the area of the base and \( h \) is the height.
First, we calculate the area of the base \( B \):
1. Length of the container: \( 20 \frac{1}{2} \) ft = \( 20.5 \) ft
2. Width of the container: \( 12 \frac{1}{4} \) ft = \( 12.25 \) ft
Now, calculate the area of the base \( B \):
\[
B = \text{Length} \times \text{Width} = 20.5 \, \text{ft} \times 12.25 \, \text{ft}
\]
Calculating it:
\[
B = 20.5 \times 12.25 = 250.625\, \text{ft}^2
\]
Next, we need to find the height \( h \):
3. Height of the container: \( 8 \frac{1}{4} \) ft = \( 8.25 \) ft
Now, we can calculate the volume \( V \):
\[
V = B \times h = 250.625 \, \text{ft}^2 \times 8.25 \, \text{ft}
\]
Calculating it:
\[
V = 250.625 \times 8.25 = 2071.15625 \, \text{ft}^3
\]
Now, converting to a fractional form, we find:
\[
2071.15625 \, \text{ft}^3 = 2071 \frac{25}{32} \, \text{ft}^3
\]
Thus, the volume of the shipping container is:
**2071 25/32 ft³**
So the correct response is:
**2,071 25/32 ft³**
First, we calculate the area of the base \( B \):
1. Length of the container: \( 20 \frac{1}{2} \) ft = \( 20.5 \) ft
2. Width of the container: \( 12 \frac{1}{4} \) ft = \( 12.25 \) ft
Now, calculate the area of the base \( B \):
\[
B = \text{Length} \times \text{Width} = 20.5 \, \text{ft} \times 12.25 \, \text{ft}
\]
Calculating it:
\[
B = 20.5 \times 12.25 = 250.625\, \text{ft}^2
\]
Next, we need to find the height \( h \):
3. Height of the container: \( 8 \frac{1}{4} \) ft = \( 8.25 \) ft
Now, we can calculate the volume \( V \):
\[
V = B \times h = 250.625 \, \text{ft}^2 \times 8.25 \, \text{ft}
\]
Calculating it:
\[
V = 250.625 \times 8.25 = 2071.15625 \, \text{ft}^3
\]
Now, converting to a fractional form, we find:
\[
2071.15625 \, \text{ft}^3 = 2071 \frac{25}{32} \, \text{ft}^3
\]
Thus, the volume of the shipping container is:
**2071 25/32 ft³**
So the correct response is:
**2,071 25/32 ft³**