What is the volume of a rectangular prism that has a height of 10 1/2 in., a length of 6 2/3

in., and a width of 2 1/4 in.? Is it large enough to hold an item that has a height of 8 in., a length of 6 in., and a width of 2 in.?(1 point)
Responses

3,780/24 in.^3

15 in.^3

157 1/2 in.^3

160 in.^3

1 answer

To find the volume of a rectangular prism, you can use the formula:

\[ \text{Volume} = \text{length} \times \text{width} \times \text{height} \]

First, let's convert the mixed numbers into improper fractions or decimals for easier computation:

  1. Height: \( 10 \frac{1}{2} = \frac{21}{2} \) inches
  2. Length: \( 6 \frac{2}{3} = \frac{20}{3} \) inches
  3. Width: \( 2 \frac{1}{4} = \frac{9}{4} \) inches

Now, substituting the values into the volume formula:

\[ \text{Volume} = \left(\frac{20}{3}\right) \times \left(\frac{9}{4}\right) \times \left(\frac{21}{2}\right) \]

Let's calculate this step by step:

  1. Calculate \( \frac{20}{3} \times \frac{9}{4} \):

\[ \frac{20 \times 9}{3 \times 4} = \frac{180}{12} = 15 \]

  1. Now multiply by \( \frac{21}{2} \):

\[ 15 \times \frac{21}{2} = \frac{315}{2} = 157.5 \]

So, the volume of the rectangular prism is:

\[ 157.5 \text{ in}^3 \]

Now, let's check if this volume can hold an item with a height of 8 in., a length of 6 in., and a width of 2 in.:

The volume of the item can also be calculated using the same formula:

\[ \text{Volume of the item} = 6 \times 2 \times 8 = 96 \text{ in}^3 \]

Since \( 157.5 \text{ in}^3 > 96 \text{ in}^3 \), the prism is large enough to hold the item.

Thus, the final answers are:

  • Volume of the rectangular prism: \( 157.5 \text{ in}^3 \)
  • Yes, it is large enough to hold the item.