Question
Solve using substitution.
x - 10y = 20
4x - 7y = -19
(_,_)
x - 10y = 20
4x - 7y = -19
(_,_)
Answers
Answered by
GPT-4o mini
To solve the system of equations using substitution, we start with the two equations:
1. \( x - 10y = 20 \)
2. \( 4x - 7y = -19 \)
First, we can solve the first equation for \( x \):
\[
x = 10y + 20
\]
Next, we substitute \( x \) in the second equation:
\[
4(10y + 20) - 7y = -19
\]
Distributing \( 4 \) in the equation:
\[
40y + 80 - 7y = -19
\]
Now combine like terms:
\[
33y + 80 = -19
\]
Next, isolate \( y \) by subtracting \( 80 \) from both sides:
\[
33y = -19 - 80
\]
\[
33y = -99
\]
Now, divide by \( 33 \) to solve for \( y \):
\[
y = -3
\]
Now that we have the value of \( y \), we can substitute it back into the expression for \( x \):
\[
x = 10(-3) + 20
\]
\[
x = -30 + 20
\]
\[
x = -10
\]
Thus, the solution to the system of equations is:
\[
(x, y) = (-10, -3)
\]
So the answer is:
\[
\boxed{(-10, -3)}
\]
1. \( x - 10y = 20 \)
2. \( 4x - 7y = -19 \)
First, we can solve the first equation for \( x \):
\[
x = 10y + 20
\]
Next, we substitute \( x \) in the second equation:
\[
4(10y + 20) - 7y = -19
\]
Distributing \( 4 \) in the equation:
\[
40y + 80 - 7y = -19
\]
Now combine like terms:
\[
33y + 80 = -19
\]
Next, isolate \( y \) by subtracting \( 80 \) from both sides:
\[
33y = -19 - 80
\]
\[
33y = -99
\]
Now, divide by \( 33 \) to solve for \( y \):
\[
y = -3
\]
Now that we have the value of \( y \), we can substitute it back into the expression for \( x \):
\[
x = 10(-3) + 20
\]
\[
x = -30 + 20
\]
\[
x = -10
\]
Thus, the solution to the system of equations is:
\[
(x, y) = (-10, -3)
\]
So the answer is:
\[
\boxed{(-10, -3)}
\]