Question

The spinner shown below is being used in a game.

A spinner has 8 sections each numbered from 1 to 8 and an arrow between 1 and 8.

What is the probability of spinning the arrow once with the result being an odd number greater than 3?

A.
5
16

B.
5
8

C.
1
2

D.
1
4

Answer 1

To determine the probability of spinning an odd number greater than 3 on a spinner that has sections numbered from 1 to 8, we can follow these steps:

1. **Identify the total possible outcomes**: The spinner has 8 sections, so there are 8 possible outcomes when you spin it (1, 2, 3, 4, 5, 6, 7, 8).

2. **Identify the favorable outcomes**: We need to find the odd numbers greater than 3. The odd numbers greater than 3 in the range from 1 to 8 are:
- 5
- 7

Therefore, the favorable outcomes are {5, 7}.

3. **Count the favorable outcomes**: There are 2 favorable outcomes (5 and 7).

4. **Calculate the probability**: The probability is given by the number of favorable outcomes divided by the total number of possible outcomes.

\[
P(\text{odd number > 3}) = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{2}{8} = \frac{1}{4}
\]

Thus, the probability of spinning the arrow once and getting an odd number greater than 3 is \( \frac{1}{4} \).

The answer is:

**D. \( \frac{1}{4} \)**