Question

A cone has a radius of 2.5 inches and a height of 1.6 inches.
What is the volume of the cone?
Use 3.14 for pi. Round to the nearest tenth.
4.0 in^3
10..5 in^3
12.0 in^3
23.1 in^3

Answer 1

The volume \( V \) of a cone can be calculated using the formula:

\[
V = \frac{1}{3} \pi r^2 h
\]

where \( r \) is the radius and \( h \) is the height.

Given:
- \( r = 2.5 \) inches
- \( h = 1.6 \) inches
- \( \pi \approx 3.14 \)

Now we can plug the values into the formula:

\[
V = \frac{1}{3} \times 3.14 \times (2.5)^2 \times 1.6
\]

Calculating \( (2.5)^2 \):

\[
(2.5)^2 = 6.25
\]

Now substituting this back into the formula:

\[
V = \frac{1}{3} \times 3.14 \times 6.25 \times 1.6
\]

Calculating \( 3.14 \times 6.25 \):

\[
3.14 \times 6.25 = 19.625
\]

Now substituting this value back in:

\[
V = \frac{1}{3} \times 19.625 \times 1.6
\]

Calculating \( 19.625 \times 1.6 \):

\[
19.625 \times 1.6 = 31.4
\]

Now we substitute this value back in:

\[
V = \frac{31.4}{3} \approx 10.4667
\]

Rounding to the nearest tenth, we get:

\[
V \approx 10.5 \text{ in}^3
\]

Thus, the volume of the cone is approximately **10.5 in³**.