Use the tables to answer the question.

Simon’s Results

This table shows the number of white and red balls Simon selected from Bowl A and Bowl B.
Number of White Balls Selected Number of Red Balls Selected
Bowl A 5 15
Bowl B 16 4
Clark’s Results

This table shows the number of white and red balls Clark selected from Bowl A and Bowl B.
Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Simon and Clark repeatedly selected a ball from both bowls and recorded the results in a table. Whose results will give you a better indication about the proportion of white and red balls in each bowl? Explain your answer.

(1 point)
Responses

Neither; they conducted the same number of trials.
Neither; they conducted the same number of trials.

Both results can be used, as they performed the experiment at random.
Both results can be used, as they performed the experiment at random.

Claark’s experiment. He conducted a greater number of trials than Simon.
Clark’s experiment. He conducted a greater number of trials than Simon.

Simon’s experiment. He conducted a greater number of trials than Clark.

1 answer

Clark’s experiment. He conducted a greater number of trials than Simon.

Clark's larger number of trials (100 total selections compared to Simon's 36) provides a more reliable estimate of the proportions of white and red balls in each bowl. More trials tend to yield results that are closer to the true proportions in the population, reducing the impact of random variation.