Question

A parent with homozygous A blood has a child with a parent who have heterozygous B. What is the probability of that child having each of these blood types (USE FRACTIONS)

Type A

Type B

Type AB

Type O

Answer 1

To determine the possible blood types of the child from a homozygous A blood type parent (genotype AA) and a heterozygous B blood type parent (genotype BO), we can use a Punnett square.

1. **Parent Genotypes**:
- Parent 1 (A blood type): AA
- Parent 2 (B blood type): BO

2. **Gametes**:
- Parent 1 can only produce gametes with A.
- Parent 2 can produce gametes with either B or O.

3. **Punnett Square**:
```
A A
-----------
B | AB | AB |
-----------
O | AO | AO |
```

4. **Possible Genotypes of the Children**:
- AB (from A and B)
- AO (from A and O)

5. **Blood Types from the Genotypes**:
- Genotype AB corresponds to blood type AB.
- Genotype AO corresponds to blood type A.

6. **Probability of Each Blood Type**:
- Type A: 2 AO (2 out of 4 possibilities) = 2/4 = 1/2
- Type B: 0 (0 out of 4 possibilities) = 0/4 = 0
- Type AB: 2 AB (2 out of 4 possibilities) = 2/4 = 1/2
- Type O: 0 (0 out of 4 possibilities) = 0/4 = 0

So, the probabilities of the child having each of the blood types are as follows:

- Type A: **1/2**
- Type B: **0**
- Type AB: **1/2**
- Type O: **0**