Question
A parent with type AB blood has a child with a parent who is type O. What is the probability of that child having each of these blood types (USE FRACTIONS)
Type A
Type B
Type AB
Type O
Type A
Type B
Type AB
Type O
Answers
GPT-4o mini
To determine the probabilities of the blood types of the child from a parent with type AB blood and a parent with type O blood, we can use the genotype of each blood type:
- Type AB: The genotype is IAIB (where IA represents the A allele and IB represents the B allele).
- Type O: The genotype is ii (where i represents the O allele).
When these two parents have a child, we can determine the possible genotypes of the child by using a Punnett square:
1. From the AB parent (IAIB), there are two possible alleles to pass on: IA and IB.
2. From the O parent (ii), there is only one possible allele to pass on: i.
Now, let's set up the Punnett square:
```
IA IB
-----------------
i | IAi | IBi |
-----------------
i | IAi | IBi |
```
From this Punnett square, we can see the possible genotypes of the children:
- IAi (which is expressed as Type A blood)
- IBi (which is expressed as Type B blood)
So the possible blood types and their probabilities are:
- Type A (IAi): 2 out of 4 = 2/4 = 1/2
- Type B (IBi): 2 out of 4 = 2/4 = 1/2
- Type AB: 0 out of 4 = 0/4 = 0
- Type O: 0 out of 4 = 0/4 = 0
Therefore, the probabilities are:
- Type A: **1/2**
- Type B: **1/2**
- Type AB: **0**
- Type O: **0**
- Type AB: The genotype is IAIB (where IA represents the A allele and IB represents the B allele).
- Type O: The genotype is ii (where i represents the O allele).
When these two parents have a child, we can determine the possible genotypes of the child by using a Punnett square:
1. From the AB parent (IAIB), there are two possible alleles to pass on: IA and IB.
2. From the O parent (ii), there is only one possible allele to pass on: i.
Now, let's set up the Punnett square:
```
IA IB
-----------------
i | IAi | IBi |
-----------------
i | IAi | IBi |
```
From this Punnett square, we can see the possible genotypes of the children:
- IAi (which is expressed as Type A blood)
- IBi (which is expressed as Type B blood)
So the possible blood types and their probabilities are:
- Type A (IAi): 2 out of 4 = 2/4 = 1/2
- Type B (IBi): 2 out of 4 = 2/4 = 1/2
- Type AB: 0 out of 4 = 0/4 = 0
- Type O: 0 out of 4 = 0/4 = 0
Therefore, the probabilities are:
- Type A: **1/2**
- Type B: **1/2**
- Type AB: **0**
- Type O: **0**