To determine which of the given graphs shows a system of equations with no solution, we first need to analyze the two equations:
- \( y = 2x + 4 \)
- \( -2x + y = 8 \)
We can rewrite the second equation in slope-intercept form (y = mx + b) to make it easier to compare slopes:
Starting with the second equation: \[ -2x + y = 8 \] Add \( 2x \) to both sides: \[ y = 2x + 8 \]
Now, we have:
- \( y = 2x + 4 \) (slope = 2, y-intercept = 4)
- \( y = 2x + 8 \) (slope = 2, y-intercept = 8)
Both lines have the same slope (2), which means they are parallel. Since the y-intercepts are different (4 and 8), these lines will never intersect and therefore represent a system of equations with no solution.
Now, to select the correct graph showing parallel lines, we look for the following characteristics:
- Both lines should be drawn parallel to each other.
- The solid line must represent \( y = 2x + 4 \) and pass through points such as (0, 4) and (2, 0).
- The dashed line must represent \( y = 2x + 8 \) and pass through points such as (0, 8) and any point corresponding to that line.
Among the options given, look for:
- A solid line passing through (0, 4) (for \( y = 2x + 4 \)).
- A dashed line passing through (0, 8) or another point consistent with \( y = 2x + 8 \).
Based on this analysis, select the graph that meets these criteria, which will indicate the correct representation of a system of equations with no solution (parallel lines).