Question
The radius of the cone is 3 in, and the height is 4 in. Find the approximate volume.
What is the approximate volume of the cone? You can use the calculator to help you solve.
You can use 3.14 as an approximation for π.
3
4
V=12π in
3
What is the approximate volume of the cone? You can use the calculator to help you solve.
You can use 3.14 as an approximation for π.
3
4
V=12π in
3
Answers
GPT-4o mini
The volume \( V \) of a cone can be calculated using the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
Where:
- \( r \) is the radius of the cone,
- \( h \) is the height of the cone,
- \( \pi \) is approximately 3.14.
In this case, the radius \( r = 3 \) inches and the height \( h = 4 \) inches.
Let's plug in the values:
\[
V = \frac{1}{3} \pi (3^2)(4)
\]
Calculate \( 3^2 \):
\[
3^2 = 9
\]
Now substitute that back into the volume formula:
\[
V = \frac{1}{3} \pi (9)(4)
\]
Now calculate \( 9 \times 4 \):
\[
9 \times 4 = 36
\]
Now substitute that into the formula:
\[
V = \frac{1}{3} \pi (36)
\]
Now calculate \( \frac{1}{3} \times 36 \):
\[
\frac{36}{3} = 12
\]
So we have:
\[
V = 12\pi
\]
Now, using \( \pi \approx 3.14 \):
\[
V \approx 12 \times 3.14
\]
Calculating the final volume:
\[
V \approx 37.68 \text{ cubic inches}
\]
Thus, the approximate volume of the cone is **37.68 cubic inches**.
\[
V = \frac{1}{3} \pi r^2 h
\]
Where:
- \( r \) is the radius of the cone,
- \( h \) is the height of the cone,
- \( \pi \) is approximately 3.14.
In this case, the radius \( r = 3 \) inches and the height \( h = 4 \) inches.
Let's plug in the values:
\[
V = \frac{1}{3} \pi (3^2)(4)
\]
Calculate \( 3^2 \):
\[
3^2 = 9
\]
Now substitute that back into the volume formula:
\[
V = \frac{1}{3} \pi (9)(4)
\]
Now calculate \( 9 \times 4 \):
\[
9 \times 4 = 36
\]
Now substitute that into the formula:
\[
V = \frac{1}{3} \pi (36)
\]
Now calculate \( \frac{1}{3} \times 36 \):
\[
\frac{36}{3} = 12
\]
So we have:
\[
V = 12\pi
\]
Now, using \( \pi \approx 3.14 \):
\[
V \approx 12 \times 3.14
\]
Calculating the final volume:
\[
V \approx 37.68 \text{ cubic inches}
\]
Thus, the approximate volume of the cone is **37.68 cubic inches**.