Question
The cylinder and the cone have the same radius, 2 in, and the same height, 6 in. The volume of the cylinder is 24π in
3
. What is the volume of the cone?
Multiply
3
1
·24 to rewrite this expression with fewer terms. What is the volume of the cone in terms of π?
2
6
V
=
πr
2
h
V
=
24π in
3
2
6
V=
3
1
πr
2
h
V
=
3
1
πr
2
h
V
=
3
1
·24π
V
=
π in
3
3
. What is the volume of the cone?
Multiply
3
1
·24 to rewrite this expression with fewer terms. What is the volume of the cone in terms of π?
2
6
V
=
πr
2
h
V
=
24π in
3
2
6
V=
3
1
πr
2
h
V
=
3
1
πr
2
h
V
=
3
1
·24π
V
=
π in
3
Answers
GPT-4o mini
To find the volume of the cone, we can start with the formula for the volume of a cone, which is given by:
\[
V = \frac{1}{3} \pi r^2 h
\]
Given that the radius (r) is 2 inches and the height (h) is 6 inches, we can substitute these values into the formula:
\[
V = \frac{1}{3} \pi (2)^2 (6)
\]
Calculating \( (2)^2 \):
\[
(2)^2 = 4
\]
Now substitute this back into the volume formula:
\[
V = \frac{1}{3} \pi (4)(6)
\]
Calculating \( 4 \times 6 \):
\[
4 \times 6 = 24
\]
Now substitute this result into the equation:
\[
V = \frac{1}{3} \pi (24)
\]
Now we can simplify further:
\[
V = \frac{24}{3} \pi
\]
Calculating \( \frac{24}{3} \):
\[
\frac{24}{3} = 8
\]
So the volume of the cone is:
\[
V = 8\pi \text{ in}^3
\]
Thus, the volume of the cone is:
\[
\boxed{8\pi} \text{ in}^3
\]
\[
V = \frac{1}{3} \pi r^2 h
\]
Given that the radius (r) is 2 inches and the height (h) is 6 inches, we can substitute these values into the formula:
\[
V = \frac{1}{3} \pi (2)^2 (6)
\]
Calculating \( (2)^2 \):
\[
(2)^2 = 4
\]
Now substitute this back into the volume formula:
\[
V = \frac{1}{3} \pi (4)(6)
\]
Calculating \( 4 \times 6 \):
\[
4 \times 6 = 24
\]
Now substitute this result into the equation:
\[
V = \frac{1}{3} \pi (24)
\]
Now we can simplify further:
\[
V = \frac{24}{3} \pi
\]
Calculating \( \frac{24}{3} \):
\[
\frac{24}{3} = 8
\]
So the volume of the cone is:
\[
V = 8\pi \text{ in}^3
\]
Thus, the volume of the cone is:
\[
\boxed{8\pi} \text{ in}^3
\]