Question
Now, divide both sides by 10π to get r
2
alone on the right side of the equation.
r = ?Area Label Arrow
height = 10
Volume = 160π
Volume
=
Area of base · Height
V
=
πr
2
·h
160π
=
πr
2
· 10
160π
=
10π·r
2
10π
10π
=
2
alone on the right side of the equation.
r = ?Area Label Arrow
height = 10
Volume = 160π
Volume
=
Area of base · Height
V
=
πr
2
·h
160π
=
πr
2
· 10
160π
=
10π·r
2
10π
10π
=
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To isolate \( r^2 \) in the equation you've provided, we start from the volume formula:
\[
160\pi = 10\pi \cdot r^2
\]
Now, divide both sides by \( 10\pi \):
\[
\frac{160\pi}{10\pi} = r^2
\]
The \(\pi\) terms cancel, and simplifying \( \frac{160}{10} \) gives:
\[
16 = r^2
\]
To find \( r \), take the square root of both sides:
\[
r = \sqrt{16}
\]
Thus, we get:
\[
r = 4
\]
So, the value of \( r \) is \( 4 \).
\[
160\pi = 10\pi \cdot r^2
\]
Now, divide both sides by \( 10\pi \):
\[
\frac{160\pi}{10\pi} = r^2
\]
The \(\pi\) terms cancel, and simplifying \( \frac{160}{10} \) gives:
\[
16 = r^2
\]
To find \( r \), take the square root of both sides:
\[
r = \sqrt{16}
\]
Thus, we get:
\[
r = 4
\]
So, the value of \( r \) is \( 4 \).
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